Odpowiedź:
Zadanie 6
a) (1 i 3/4)² = (7/4)² = 49/16 = 3 i 1/16
b) (-1 i 2/5)³ = (-7/5) • (-7/5) • (-7/5) = -343/125 = -2 i 93/125
c) (-3 i 4/7)² = (-25/7)² = 625/49 = 12 i 37/49
d) (2 i 1/3)³ = 7/3 • 7/3 • 7/3 = 343/27 = 12 i 19/27
Szczegółowe wyjaśnienie:
(1 3/4)^2=(7/4)^2=49/16=3 1/16
(-1 2/5)^3= (-7/5)^3= - 343/125= -2 93/125
(-3 4/7)^2= (-25/7)^2=625/49=12 37/49
(2 1/3)^3=(7/3)^3=343/27=12 19/27
