Odpowiedź :
[tex]a = x+2\\b = 3\\c = 2,5\cdot2\\\\\\Z \ tw. \ Pitagorasa:\\\\a^{2}+b^{2} = c^{2}\\\\(x+2)^{2}+3^{2} = (2,5\cdot2)^{2}\\\\(x+2)^{2} +9 = 5^{2}\\\\(x+2)^{2} = 25-9\\\\(x+2)^{2} = 16\\\\(x+2)^{2} = 4^{2} \ \ |\sqrt{}\\\\x+2 = 4\\\\x = 4-2\\\\\boxed{x = 2}[/tex]