Odpowiedź:
[tex]\huge\boxed{\boxed{\text{wynik}\Longrightarrow2\frac{21}{80}}}[/tex]
Szczegółowe wyjaśnienie:
Obliczenia
[tex]1\frac{1}{8}\cdot(4\frac{3}{5}-2\frac{7}{10})+(\frac{1}{2})^3=\frac{1\cdot8+1}{8}\cdot(4\frac{3\cdot2}{5\cdot2}-2\frac{7}{10})+\frac{1^3}{2^3}=\\\\=\frac{8+1}{8}\cdot(4\frac{6}{10}-2\frac{7}{10})+\frac{1\cdot1\cdot1}{2\cdot2\cdot2}=\frac{9}{8}\cdot(3\frac{16}{10}-2\frac{7}{10})+\frac{1}{8}=\\\\=\frac{9}{8}\cdot1\frac{9}{10}+\frac{1}{8}=\frac{9}{8}\cdot\frac{19}{10}+\frac{1}{8}=\frac{171}{80}+\frac{1\cdot10}{8\cdot10}=\frac{171}{80}+\frac{10}{80}=\frac{181}{80}=2\frac{21}{80}[/tex]