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[tex]\sqrt{20}=\sqrt{4\cdot5}=\sqrt{2^2\cdot5}=2\sqrt5\\\\\sqrt{45}=\sqrt{9\cdot5}=\sqrt{3^2\cdot5}=3\sqrt5\\\\\sqrt{108}=\sqrt{36\cdot3}=\sqrt{6^2\cdot3}=6\sqrt3\\\\\sqrt[3]{48}=\sqrt[3]{8\cdot6}=\sqrt[3]{2^3\cdot6}=2\sqrt[3]6\\\\\sqrt[3]{128}=\sqrt[3]{64\cdot2}=\sqrt[3]{4^3\cdot2}=4\sqrt[3]2\\\\\sqrt{12}=\sqrt{4\cdot3}=\sqrt{2^2\cdot3}=2\sqrt3[/tex]