[tex]Dane:\\F_1 = 60 \ N\\S_1 = 40 \ cm^{2}\\S_2 = 100 \ cm^{2}\\g = 10\frac{N}{kg}\\Szukane:\\F_2 = ?\\\\Rozwiazanie\\\\Z \ prawa \ Pascala\\\\\frac{F_1}{S_1} = \frac{F_2}{S_2} = p = constans\\\\F_2\cdot S_1 = F_1 \cdot S_2\\\\ale\\\\F_2 = m_2\cdot g\\\\m_2\cdot g\cdot S_1 = F_1\cdot S_2 \ \ /:(g\cdot S_1)[/tex]
[tex]m_2 = \frac{F_1\cdot S_2}{g\cdot S_1}\\\\m_2 = \frac{60 \ N\cdot100 \ cm^{2}}{10\frac{N}{kg}\cdot40 \ cm^{2}}\\\\\boxed{m_2 = 15 \ kg}[/tex]
Odp. Ten podnośnik hydrauliczny może podnieść masę m₂ = 15 kg.
