Odpowiedź:
[tex]\huge\boxed{\boxed{m_{\text{MgCl}_2}=94 \ u}}}[/tex]
[tex]\huge\boxed{\boxed{m_{\text{N}_2\text{O}_5}=108 \ u}}[/tex]
[tex]\huge\boxed{\boxed{m_{\text{H}_2\text{SO}_4}=98 \ u}}[/tex]
[tex]\huge\boxed{\boxed{m_{\text{C}_2\text{H}_5\text{OH}}=46 \ u}}[/tex]
[tex]\huge\boxed{\boxed{m_{\text{Al}(\text{NO}_3)_3}=213 \ u}}[/tex]
Wyjaśnienie:
Obliczenia dla MgCl₂
[tex]m_{\text{Mg}}=24 \ u\\\\m_{\text{Cl}}=35 \ u\\\\m_{\text{MgCl}_2}=24 \ u+2\cdot35 \ u=24 \ u+70 \ u=94 \ u[/tex]
Obliczenia dla N₂O₅
[tex]m_\text{N}=14 \ u\\\\m_\text{O}=16 \ u\\\\m_{\text{N}_2\text{O}_5}=2\cdot14 \ u+5\cdot16 \ u=28 \ u+80 \ u=108 \ u[/tex]
Obliczenia dla H₂SO₄
[tex]m_\text{H}=1 \ u\\\\m_\text{S}=32 \ u\\\\m_\text{O}=16 \ u\\\\m_{\text{H}_2\text{SO}_4}=2\cdot1 \ u+32 \ u+4\cdot16 \ u=2 \ u+32 \ u+64 \ u=98 \ u[/tex]
Obliczenia dla C₂H₅OH
[tex]m_\text{C}=12 \ u\\\\m_\text{H}=1 \ u\\\\m_\text{O}=16 \ u\\\\m_{\text{C}_2\text{H}_5\text{OH}}=2\cdot12 \ u+6\cdot1 \ u+16 \ u=24 \ u+6 \ u+16 \ u=46 \ u[/tex]
Obliczenia dla Al(NO₃)₃
[tex]m_\text{Al}=27 \ u\\\\m_\text{N}=14 \ u\\\\m_\text{O}=16 \ u\\\\m_{\text{Al}(\text{NO}_3)_3}=27 \ u+3\cdot14 \ u+9\cdot16 \ u=27 \ u+42 \ u+144 \ u=213 \ u[/tex]
