Odpowiedź:
[tex]a)\\\\(3x+1)(x+2)-3(x-1)(x-2)=5+x\\\\3x^2+6x+x+2-3(x^2-2x-x+2)=5+x\\\\3x^2+7x+2-3(x^2-3x+2)=5+x\\\\3x^2+7x+2-3x^2+9x-6=5+x\\\\16x-4=5+x\\\\16x-x=5+4\\\\15x=9\ \ /:15\\\\x=\frac{9}{15}\\\\x=\frac{3}{5}\\\\\\b)\\\\0,5(2x-4)+4=-x+2\\\\x-2+4=-x+2\\\\x+2=-x+2\\\\x+x=2-2\\\\2x=0\ \ /:2\\\\x=0[/tex]
[tex]c)\\\\\frac{x+2}{4}-\frac{x}{2}=\frac{3(x-2)}{4}\\\\\frac{x+2}{4}-\frac{x}{2}=\frac{3x-6}{4}\ \ /\cdot4\\\\x+2-2x=3x-6\\\\-x+2=3x-6\\\\-x-3x=-6-2\\\\-4x=-8\ \ /:(-4)\\\\x=2\\\\\\d)\\\\(x-1)^2-(x+4)^2=-2x+1\\\\x^2-2x+1-(x^2+8x+16)=-2x+1\\\\x^2-2x+1-x^2-8x-16=-2x+1\\\\-10x-15=-2x+1\\\\-10x+2x=1+15\\\\-8x=16\ \ /:(-8)\\\\x=-2[/tex]
[tex]e)\\\\(2-x)(2+x)+(x+3)^2=x-7\\\\4-x^2+x^2+6x+9=x-7\\\\6x+13=x-7\\\\6x-x=-7-13\\\\5x=-20\ \ /:5\\\\x=-4[/tex]
