Odpowiedź :
Zad. 1
b)
[tex]\frac{2}{3*3-2}=\frac{2}{9-2}=\frac{2}{7}[/tex]
d)
[tex]2*4+4^{2} =8+16=24[/tex]
f)
[tex]3*4-1=12-1=11[/tex]
h)
[tex]5(5+2)=5*7=35[/tex]
Odpowiedź:
b) [tex]\frac{2}{3b-2} =\frac{2}{3*3-2} =\frac{2}{9-2} =\frac{2}{7}[/tex]
d) 2x + x² = 2*4 + 4² = 8 + 16 = 24
f) 3m - 1 = 3*4 - 1 = 12 - 1 = 11
h) t(t + 2) = 5(5 + 2) = 5 * 7 = 35