Odpowiedź:
zad 1
[tex]a=9cm\\c=14cm\\a^{2} +b^{2} =c^{2} \\81cm^{2} +b^{2}=196cm^{2} \\b^{2} =196cm^{2}-81cm^{2}=115cm^{2} \\b=\sqrt{115}cm\\B[/tex]
zad 2.
[tex]a=1,8m\\b=x\\c=x+0,2m\\a^{2} +b^{2} =c^{2} \\3,24m^{2} +x^{2} =(x+0,2m)^{2} =x^{2} +0,4x+0,04m^{2} \\3,2m=0,4x\\x=\frac{3,2m}{0,4}=8m\\b=8m\\[/tex]
zad 3.
a)
[tex]c^{2} =7^{2} +24^{2} =49+576=625\\c=\sqrt{625}=25\\[/tex]
b)
[tex]c^{2} =5^{2} +6^{2} =25+36=61\\c=\sqrt{61} \\[/tex]
c)
[tex]12^{2} +b^{2} =13^{2} \\144+b^{2} =169\\b^{2} =25\\b=\sqrt{25} =5\\[/tex]
zad 4.
[tex]a=8\sqrt{3} \\c=10\sqrt{3} \\a^{2} +b^{2} =c^{2} \\(8\sqrt{3})^{2} +b^{2} =(10\sqrt{3} )^{2} \\192+b^{2} =300\\b^{2} =300-192=108\\b=\sqrt{108} =6\sqrt{3} \\P=a*b=\frac{8\sqrt{3}*6\sqrt{3}}{2} =\frac{144}{2} =72\\C[/tex]
zad 5.
[tex]a=24cm\\c=51cm\\a^{2} +b^{2} =c^{2} \\(24cm)^{2}+b^{2}=(51cm)^{2}\\576cm^{2}+b^{2}=2601cm^{2}\\b^{2}=2601cm^{2}-576cm^{2}=2025cm^{2}\\b=\sqrt{2025cm^{2}}=45cm \\OBW=a+b+c=24cm+51cm+45cm=120cm[/tex]
zad 6.
1) PRAWDA
2) PRAWDA
