[tex]zad.3\\\\a)~~\dfrac{9}{\sqrt{9} } =\dfrac{9}{3} =3~~-liczba ~~wymierna\\\\b)~~\dfrac{\sqrt{8 } }{8} =\dfrac{2\sqrt{2} }{8}=\dfrac{\sqrt{2} }{4}=\dfrac{1}{4} \cdot \sqrt{2} ~~-liczba~~niewynierna\\\\c)~~6\sqrt{7} -6\sqrt{7}=0~~-liczba~~wymierna\\\\d)~~\dfrac{\sqrt{6} }{\sqrt{6} } =1~~-liczba~~wymierna\\\\Odp:~~B[/tex]
[tex]zad.4\\\\\sqrt[3]{\sqrt{81} -1} =\sqrt[3]{\sqrt{9^{2} } -1} =\sqrt[3]{9-1} =\sqrt[3]{8} =\sqrt[3]{2^{3} } =2^{3\cdot \frac{1}{3} } =2^{1} =2\\\\Odp:~~A[/tex]
