[tex]7\frac{10}{35}+5\frac{4\cdot5}{7\cdot5}-3\frac{2\cdot7}{5\cdot7}=\\\\=7\frac{10}{35}+5\frac{20}{35}-3\frac{14}{35}=\\\\=12\frac{30}{35}-3\frac{14}{35}=\\\\=\boxed{9\frac{16}{35}}\\\\\\1\frac{13}{25}+\frac{17}{25}-1\frac{4\cdot5}{5\cdot5}=\\\\=3\frac{5}{25}-1\frac{20}{25}=\\\\=\boxed{1\frac{10\div5}{25\div5}=1\frac{2}{5}}[/tex]
