Odpowiedź:
6
a) Pole
[tex] \sqrt[3]{4} \times \sqrt[3]{16} = \sqrt[3]{64} = 4[/tex]
obwód
[tex]2 \times \sqrt[3]{4} + 2 \times \sqrt[3]{16} = 2 \sqrt[3]{4} + 2 \sqrt[3]{16} [/tex]
b) Pole
[tex] \sqrt{5} \times \sqrt{20} = \sqrt{100} = 10 [/tex]
obwód
[tex]5 + \sqrt{5} + \sqrt{20} = 5 + \sqrt{5} + 2 \sqrt{5} = 5 + 3 \sqrt{5} [/tex]
c) Pole
[tex] \frac{( \sqrt{2} + \sqrt{32}) \times 4 \sqrt{2} }{2} = ( \sqrt{2} + 4 \sqrt{2} ) \times 2 \sqrt{2} = 5 \sqrt{2} \times 2 \sqrt{2} = 20[/tex]
obwód
[tex] \sqrt{2} + 5\sqrt{2} + 4 \sqrt{2} + 4 \sqrt{2} = 14 \sqrt{2} [/tex]
d) Pole
[tex] \frac{8 \sqrt{3} \times 6 \sqrt{3} }{2} = 4 \sqrt{3} \times 6 \sqrt{3} = 24 \times 3 = 72[/tex]
obwód
[tex]4 \times \sqrt{75} = 4 \times 5 \sqrt{3} = 20 \sqrt{3} [/tex]
e) pole
[tex] \frac{(3 \sqrt{5} + 6 \sqrt{5}) \times 2 \sqrt{5} }{2} = 9 \sqrt{5} \times \sqrt{5} = 9 \times 5 = 45[/tex]
obwód
[tex]3 \sqrt{5} + 5 + 6 \sqrt{5} + 2 \sqrt{10} = 9 \sqrt{5} + 5 + 2 \sqrt{10} [/tex]
f) pole
[tex] \frac{(2 \sqrt{2} + \sqrt{32} ) \times 2}{2} = 2 \sqrt{2} + 4 \sqrt{2} = 6 \sqrt{2} [/tex]
obwód
[tex]4 \sqrt{2} + 2 \sqrt{3} + 2 + 2 \sqrt{2} = 6 \sqrt{2} + 2 \sqrt{3} + 2[/tex]
