[tex]F_1 = 12 \ N\\a_1 = 3\frac{m}{s^{2}}\\a_2 = 1\frac{m}{s^{2}}\\Szukane:\\F_2}=?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m} \ \ \rightarrow \ \ m = \frac{F}{a}\\\\m = \frac{F_1}{a_1}\\oraz\\m = \frac{F_2}{a_2}\\\\\frac{F_1}{a_1} = \frac{F_2}{a_2}\\\\F_2\cdot a_1 = F_1\cdot a_2 \ \ /:a_1\\\\F_2 = F_1\cdot\frac{a_2}{a_1}[/tex]
[tex]F_2 = 12 \ N\cdot\frac{1\frac{m}{s^{2}}}{3\frac{m}{s^{2}}}}=\frac{12 \ N}{3}\\\\\boxed{F_2 = 4 \ N}[/tex]
Odp. Na to ciało powinna działać siła F₂ = 4 N.
