Odpowiedź:
[tex]\huge\boxed{\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{3}{6}+\dfrac{2}{6}=\dfrac{5}{6}}\\\boxed{\dfrac{3}{4}-\dfrac{2}{3}=\dfrac{9}{12}-\dfrac{8}{12}=\dfrac{1}{12}}[/tex]
Szczegółowe wyjaśnienie:
[tex]\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{1\cdot3}{2\cdot3}+\dfrac{1\cdot2}{3\cdot2}=\dfrac{3}{6}+\dfrac{2}{6}=\dfrac{3+2}{6}=\dfrac{5}{6}\\\\\dfrac{3}{4}-\dfrac{2}{3}=\dfrac{3\cdot3}{4\cdot3}-\dfrac{2\cdot4}{3\cdot4}=\dfrac{9}{12}-\dfrac{8}{12}=\dfrac{9-8}{12}=\dfrac{1}{12}[/tex]
