Odpowiedź:
zad7
a)[tex]\sqrt{131^2}=131[/tex]
b)[tex]\sqrt{19} *2*\sqrt{19} =2\sqrt{19^2} =2*19=38[/tex]
c)[tex]\sqrt{3} *\sqrt{6} *\sqrt{2} =\sqrt{3*6*2} =\sqrt{36} =6[/tex]
zad8
a)[tex]2\sqrt{3} =\sqrt{2^2*3} =\sqrt{12}[/tex]
b)[tex]3\sqrt{3} =\sqrt{3^2*3} =\sqrt{27}[/tex]
c)[tex]5\sqrt{2} =\sqrt{5^2*2} =\sqrt{50}[/tex]
[tex]5\sqrt{5} =\sqrt{5^2*5} =\sqrt{125}[/tex]
e)[tex]3\sqrt[3]{3} =\sqrt[3]{3^3*3}=\sqrt[3]{81}[/tex]
f)[tex]10\sqrt[3]{3} =\sqrt[3]{10^3*3} =\sqrt[3]{3000}[/tex]
zad9
a)[tex]\frac{4}{\sqrt{2} } *\frac{\sqrt{2} }{\sqrt{2} } =\frac{4\sqrt{2} }{2} =2\sqrt{2}[/tex]
b)[tex]\frac{3}{2\sqrt{2} } *\frac{\sqrt{2} }{\sqrt{2} } =\frac{3\sqrt{2} }{2*2} =\frac{3\sqrt{2} }{4}[/tex]
c)[tex]\frac{4}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =\frac{4\sqrt{3} }{3}[/tex]
d)[tex]\frac{6}{5\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =\frac{6\sqrt{3} }{5*3} =\frac{2\sqrt{3} }{5}[/tex]
zad 10
wzór na pole prostokąta
P=a*b
wzór na obwód prostokąta
O=2a+2b
a) P=3√2*√2
P=3*2=6cm²
P=6cm²
O=2*3√2+2*√2=6√2+2√2
O=8√2 cm
b)P=√12*√3
P=√36=6 cm²
P=6cm²
O=2*√12+2*√3=2*2√3+2√3
O=4√3+2√3=6√3
O=6√3 cm
Szczegółowe wyjaśnienie:
