Odpowiedź:
[tex]a)\\\\5\frac{3}{4}+x=7\frac{1}{3}\\\\x=7\frac{1}{3}-5\frac{3}{4}\\\\x=7\frac{4}{12}-5\frac{9}{12}\\\\x=6\frac{16}{12}-5\frac{9}{12}\\\\x=1\frac{7}{12}\\\\\\b)\\\\x+1\frac{2}{7}=4\frac{4}{5}\\\\x=4\frac{4}{5}-1\frac{2}{7}\\\\x=4\frac{28}{35}-1\frac{10}{35}\\\\x=3\frac{18}{35}[/tex]
[tex]c)\\\\x-1\frac{3}{4}=2\frac{5}{6}\\\\x=2\frac{5}{6}+1\frac{3}{4}\\\\x=2\frac{10}{12}+1\frac{9}{12}\\\\x=3\frac{19}{12}\\\\x=4\frac{7}{12}\\\\\\d)\\\\4\frac{2}{3}-x=\frac{3}{8}\\\\-x=\frac{3}{8}-4\frac{2}{3}\\\\-x=\frac{3}{8}-\frac{14}{3}\\\\-x=\frac{9}{24}-\frac{112}{24}\\\\-x=-\frac{103}{24}\ \ /\cdot(-1)\\\\x=\frac{103}{24}\\\\x=4\frac{7}{24}[/tex]
