Odpowiedź:
[tex]\sqrt{8-\frac{8}{9}}-\sqrt{(\frac{8}{9})^{2}}=\\\\=\sqrt{\frac{72}{9}-\frac{8}{9}}-\sqrt{(\frac{8}{9})^{2}}=\\\\=\sqrt{\frac{64}{9}}-\sqrt{(\frac{8}{9})^{2}}=\\\\=\sqrt{(\frac{8}{3})^{2}}-\sqrt{(\frac{8}{9})^{2}}=\\\\=\frac{8}{3}-\frac{8}{9}=\\\\=\frac{24}{9}-\frac{8}{9}=\\\\=\frac{16}{9}=\\\\=1\frac{7}{9}[/tex]
Szczegółowe wyjaśnienie:
