Odpowiedź:
[tex]2\sqrt{3}(\sqrt{27}+3\sqrt{6}-2\sqrt{3})=2\sqrt{3}(3\sqrt{3}+3\sqrt{6}-2\sqrt{3})= 2\sqrt{3}(\sqrt{3}+3\sqrt{6} )=6+6\sqrt{18} =6+18\sqrt{2}[/tex]
