x+2=1/x ile to x 2c+d=4a*b ile to a 8x/2y = 4 ile to y 12x/4=x do kwadratu*t ile to te błagam szybko daje naj proszę​



Odpowiedź :

a)

[tex]x+2=\frac1{x} /*x\\x(x+2)=1\\x^2+2x=1\\x^2+2x-1=0\\\Delta=2^2-4*1*(-1)\\\Delta=4+4\\\Delta=8\\\sqrt{\Delta}=\sqrt{8}=2\sqrt2\\x_1=\frac{-2-2\sqrt2}2=\frac{2(-1-\sqrt2)}2=-1-\sqrt2\\x_2=\frac{-2+2\sqrt2}2=\frac{2(-1+\sqrt2)}2=-1+\sqrt2[/tex]

[tex]b)\\2c+4=4a*b\\2c+4=4ab /:(4b)\\\frac{2c+4}{4b}=a\\\frac{2(c+2)}{4b}=a\\\frac{c+2}{2b}=a\\\frac{c}{2b}+\frac1b=a[/tex]

[tex]c)\\\frac{8x}{2y}=4 /*2y\\8x=4*2y\\8x=8y /:8\\y=x[/tex]

[tex]d)\\\frac{12x}4=x^2*t /*\frac{1}{x^2}\\t=\frac{12x}4*\frac{1}{x^2}\\t=3x*\frac{1}{x^2}\\t=\frac{3x}{x^2}\\t=\frac{3}x[/tex]