Odpowiedź:
N = 14u
3H = 3 * 1u = 3u
NH3 = 14u + 3u = 17u
17 - 100%
14 = x%
x = 1400/17
x = 82,4% (dla N)
17 - 100%
3 - x%
x = 300/17
x = 17,6% (dla H)
2K = 2 * 39u = 78u
O = 16u
K2O = 16u + 78u = 94u
94 - 100%
78 - x
x = 7800/94
x = 83% (dla K)
94 - 100%
16 - x%
x = 1600/94
x = 17% (dla O)
Ca = 40u
2N = 2 * 14 = 28u
6O = 6 * 16 = 96u
Ca(NO3)2 = 40u + 28u + 96u = 164u
164 - 100%
40 -x%
x = 4000/164
x = 24,4% (dla Ca)
164 - 100%
28 - x%
x = 2800/164
x = 17,1% (dla N)
164 = 100%
96 = x%
x = 9600/164
x = 58,5% (dla O)
Wyjaśnienie: