Odpowiedź:
[tex]\boxed{a)=2\frac{3}{10}}\boxed{b)=3\frac{5}{14}}\boxed{c)=6\frac{11}{15}}\boxed{d)=3\frac{11}{18}}[/tex]
Szczegółowe wyjaśnienie:
[tex]2\frac{1}{5}+\frac{1}{10}=2\frac{1\cdot2}{5\cdot2}+\frac{1}{10}=2\frac{2}{10}+\frac{1}{10}=2\frac{3}{10}\\\\2\frac{1}{7}+1\frac{3}{14}=2\frac{1\cdot2}{7\cdot2}+1\frac{3}{14}=2\frac{2}{14}+1\frac{3}{14}=3\frac{5}{14}\\\\2\frac{2}{5}+4\frac{1}{3}=2\frac{2\cdot3}{5\cdot3}+4\frac{1\cdot5}{3\cdot5}=2\frac{6}{15}+4\frac{5}{15}=6\frac{11}{15}\\\\1\frac{1}{6}+2\frac{4}{9}=1\frac{1\cdot3}{6\cdot3}+2\frac{4\cdot2}{9\cdot2}=1\frac{3}{18}+2\frac{8}{18}=3\frac{11}{18}[/tex]
