Z twierdzenia Pitagorasa:
a² + b² = c²
gdzie:
a,b - przyprostokątne
c - przeciwprostokątna
[tex]1)\\a^{2}+\sqrt{5}^{2} = \sqrt{14}^{2}\\\\a^{2}+5 = 14\\\\a^{2} = 14-5\\\\a^{2} = 9\\\\a = \sqrt{9}\\\\\boxed{a = 3}[/tex]
[tex]2)\\4^{2}+5^{2} = b^{2}\\\\16+25 = b^{2}\\\\b^{2} = 41\\\\\boxed{b = \sqrt{41}}[/tex]