Odpowiedź:
2.
a) ∛8 = 2 bo 2³ = 8
b) ∛64 = 4 bo 4³ = 64
c) ∛1000 000 = 100 bo 100³ = 1000 000
d) ∛27 000 = 30 bo 30³ = 27 000
e) ∛125 000 = 50 bo 50³ = 125 000
2.
(1½)³ = (2/2 + 1/2)³ = (3/2)³ = 27/8
bo ∛(3i3/8) = ∛(24/8 + 3/8) =∛27/8 = 3/2 = 1½
0,5³ = 0,125 bo ∛0,125 = 0,5
0,04³ = 0,000064 bo ∛0,000064 = 0,04
(2/3)³ = 8/27 bo ∛(8/27) = 2/3
Szczegółowe wyjaśnienie:
2.
a) ∛8 = 2 bo 2³ = 8
b) ∛64 = 4 bo 4³ = 64
c) ∛1000 000 = 100 bo 100³ = 1000 000
d) ∛27 000 = 30 bo 30³ = 27 000
e) ∛125 000 = 50 bo 50³ = 125 000
2.
(1½)³ = (2/2 + 1/2)³ = (3/2)³ = 27/8
bo ∛(3i3/8) = ∛(24/8 + 3/8) =∛27/8 = 3/2 = 1½
0,5³ = 0,125 bo ∛0,125 = 0,5
0,04³ = 0,000064 bo ∛0,000064 = 0,04
(2/3)³ = 8/27 bo ∛(8/27) = 2/3
