Odpowiedź:
Liczę na naj!
Szczegółowe wyjaśnienie:
Zad 12:
a) [tex]4+1\frac{1}{5}*\frac{3}{4}=4+\frac{6}{5}*\frac{3}{4}=4+\frac{3}{5}*\frac{3}{2}=4+\frac{9}{10}=\frac{49}{10}=4\frac{9}{10}[/tex]
b) [tex]2\frac{1}{4}:(2\frac{5}{6}-1\frac{1}{3})-\frac{1}{6}=\frac{9}{4}:(\frac{17}{6}-\frac{4}{3})-\frac{1}{6}=\frac{9}{4}:\frac{3}{2}-\frac{1}{6}=\frac{9}{4}*\frac{2}{3}-\frac{1}{6}=\frac{3}{2}-\frac{1}{6}=\frac{4}{3} =1\frac{1}{3}[/tex]
Zad 9:
a) [tex]\frac{5}{9}:10+1\frac{2}{3}:6=\frac{5}{9}*\frac{1}{10}+\frac{5}{3}*\frac{1}{6}=\frac{1}{9}*\frac{1}{2}+\frac{5}{18}=\frac{1}{18}+\frac{5}{18}=\frac{1}{3}[/tex]
b) [tex](2\frac{7}{10}-1\frac{1}{5})^{2}:4=(\frac{27}{10}-\frac{6}{5})^{2}*\frac{1}{4}=(\frac{3}{2})^{2}*\frac{1}{4}=\frac{9}{4}*\frac{1}{4}=\frac{9}{16}[/tex]
