Odpowiedź:
pH = ?
α = ?
C₀ = 0,5 M
Kₐ = 8,3 · 10⁻⁴
[tex]\frac{Cm}{K} = \frac{0,5}{8,3*10^-4} = 602,409... > 400[/tex]
K = α² · C₀ -> [tex]\alpha = \sqrt{\frac{K}{C_{0} } }[/tex]
α = √0,00166 ≈ 0,0407
[tex]\alpha = \frac{C_{z} }{C_{0} } => C_{z} = \alpha * C_{0} = 0,0407*0,5 = 0,02035 M[/tex]
pH = -log[H⁺] = - log[0,02035] ≈ 1,7
