Odpowiedź :
[tex]Dane:\\F_1 = 80 \ N\\S_1 = 3 \ m^{2}\\S_2 = 9 \ m^{2}\\Szukane:\\F_2}=?\\\\Z \ prawa \ Pascala\\\\\frac{F_1}{S_1} = \frac{F_2}{S_2}\\\\S_1\cdot F_2 = S_2\cdot F_1 \ \ /:S_1\\\\F_2 = \frac{S_2}{S_1}\cdot F_1\\\\F_2 = \frac{9 \ m^{2}}{3 \ m^{2}}\cdot 80 \ N\\\\\boxed{F_2 = 240 \ N}[/tex]