A)
[tex]4(x-3) = -2(3x-4)\\\\4x - 12 = -6x +8\\\\4x+6x = 8+12\\\\10x =20 \ \ /:10\\\\\boxed{x = 2}[/tex]
B)
[tex]2x+\frac{1}{2}=5x+\frac{4}{3} \ \ /\cdot6\\\\6\cdot2x+6\cdot\frac{1}{2} = 5x\cdot6 + 6\cdot\frac{4}{3}\\\\12x+3 = 30x +8\\\\12x-30x = 8-5\\\\-18x = 3 \ \ /:(-18)\\\\\boxed{x = -\frac{1}{6}}[/tex]
C)
[tex]\frac{1}{x}=\frac{-3}{x-8}\\\\\\Zal.\\x \neq 0 \ \ i \ \ x\neq 8\\D = R \setminus\{0,8\}\\\\\\x-8 = -3x\\\\x+3x = 8\\\\4x = 8 \ \ /:4\\\\\boxed{x = 2}[/tex]
