[tex](1\frac{1}{8} +0,625)\cdot3,6\cdot10=(1\frac{1}{8}+\frac{5}{8} )\cdot36=1\frac{6}{8}\cdot36= 1\frac{3}{8} \cdot36=\\\\\frac{11}{8}\cdot36=\frac{x}{y} =\frac{11}{4\cdot2} \cdot\frac{4\cdot9}{1}=\frac{11}{2}\cdot \frac{9}{1} = \frac{99}{2} =49\frac{1}{2}[/tex]
