Odpowiedź:
[tex]Zad.1\\\\\sqrt{81}=\sqrt{9^2}=9\\\\\sqrt[3]{125}=\sqrt[3]{5^3}=5\\\\\sqrt{3\frac{6}{25}}=\sqrt{\frac{81}{25}}=\frac{9}{5}=1\frac{4}{5}\\\\\sqrt{0,5}\cdot\sqrt{800}=\sqrt{0,5\cdot800}=\sqrt{400}=20\\\\\sqrt[3]{10}\cdot\sqrt[3]{100}=\sqrt[3]{10\cdot100}=\sqrt[3]{1000}=\sqrt[3]{10^3}=10\\\\\sqrt{\frac{2}{27}}:\sqrt{\frac{2}{3}}=\sqrt{\frac{2}{27}:\frac{2}{3}}=\sqrt{\frac{\not2^1}{\not27_{9}}\cdot\frac{\not3^1}{\not2_{1}}}=\sqrt{\frac{1}{9}}=\frac{1}{3}[/tex]
[tex]\sqrt[3]{40}:\sqrt[3]{\frac{5}{8}}=\sqrt[3]{40:\frac{5}{8}}=\sqrt[3]{\not40^8\cdot\frac{8}{\not5_{1}}}=\sqrt[3]{8\cdot8}=\sqrt[3]{64}=4\\\\\\Zad.2\\\\5\sqrt{3}=\sqrt{5^2\cdot3}=\sqrt{25\cdot3}=\sqrt{75}\\\\3\sqrt[3]{16}=\sqrt[3]{3^3\cdot16}=\sqrt[3]{27\cdot16}=\sqrt[3]{432}[/tex]
