Odpowiedź:
[tex]c)\ \ (x-5)^2-3(x-1)(x+1)-(2x^2-1)+x(2x-3)=\\\\=x^2-10x+25-3(x^2-1)-2x^2+1+2x^2-3x=\\\\=x^2-10x+25-3x^2+3+1-3x=-2x^2-13x+29\\\\\\d)\ \ (4+x)(4-x)-2x(1-3x)+2(x+2)^2-4(x^2-1)=\\\\=16-x^2-2x+6x^2+2(x^2+4x+4)-4x^2+4=\\\\=16+5x^2-2x+2x^2+8x+8-4x^2+4=3x^2+6x+28[/tex]
