Odpowiedź :
[tex]1,2\cdot\dfrac{7}{12}-\dfrac{0,25}{0,5}+\dfrac{0,3\cdot0,6}{0,18} = \dfrac{12}{10}\cdot\dfrac{7}{12}-0,5+\dfrac{0,18}{0,18} = \dfrac{7}{10}-0,5+1 =0,7-0,5+1 =\\\\= 1,2[/tex]
[tex]1,2\cdot\dfrac{7}{12}-\dfrac{0,25}{0,5}+\dfrac{0,3\cdot0,6}{0,18} = \dfrac{12}{10}\cdot\dfrac{7}{12}-0,5+\dfrac{0,18}{0,18} = \dfrac{7}{10}-0,5+1 =0,7-0,5+1 =\\\\= 1,2[/tex]