Odpowiedź:
[tex]a)\ \ x^2-x\ \ \ \ dla\ \ x=7\\\\x^2-x=7^2-7=49-7=42\\\\\\b)\ \ a^2-3a+1\ \ \ \ dla\ \ a=-4\\\\a^2-3a+1=(-4)^2-3\cdot(-4)+1=16+12+1=28+1=29\\\\\\c)\ \ 1+x(x+4)\ \ \ \ dla\ \ x=-11\\\\1+x(x+4)=1+(-11)\ \cdot(-11+4)=1+(-11)\cdot(-7)=1+77=78\\\\\\d)\ \ x-2y\ \ \ \ dla\ \ x=1\ \ i\ \ y=-1\\\\x-2y=1-2\cdot(-1)=1+2=3\\\\\\e)\ \ 2x^2-y(x+1)\ \ \ \ dla\ \ x=-2\ \ i\ \ y=5\\\\2x^2-y(x+1)=2\cdot(-2)^2-5(-2+1)=2\cdot4-5\cdot(-1)=8+5=13\\\\\\f)\ \ (m+1)(n-2)\ \ \ \ dla\ \ m=2\ \ i\ \ n=1[/tex]
[tex](m+1)(n-2)=(2+1)(1-2)=3\cdot(-1)=-3[/tex]
