[tex]bok:\ a=?\\wysokosc\ rownolegloboku\ opadajaca\ na \ bok \ a:\ \ h=10\\\\bok:\ b=20\\wysokosc\ rownolegloboku\ opadajaca\ na\ bok \ b :\ h_{1}=14\\\\ obliczamy\ pole\ rownolegloboku \ o boku\ b\ i\ wysokosci\ h_{1}:\\\\P=b*h_{1}\\\\P=20*14=280\ [j^2][/tex]
[tex] pole\ rownolegloboku \ o boku\ a\ i\ wysokosci\ ha:\\\\P=a*h\\\\ pole\ wynosi:\ P=280\ [j^2]\ wiec :\\\\a*10=280\ \ |:10\\\\a=28 \\\\odp.\ Dlugosc\ boku\ a =\boxed{28}[/tex]
