[tex]Dane:\\S = 5 \ m^{2}\\h = 100 \ m\\d = 1030\frac{kg}{m^{3}} \ - \ gestosc \ wody \ slonej\\g = 10\frac{m}{s^{2}} = 10\frac{N}{kg}\\Szukane:\\F = ?\\\\Rozwiazanie\\\\p = \frac{F}{S} \ \ i \ \ p = d\cdot g\cdot h\\\\\frac{F}{S} = d\cdot g\cdot h \ \ /\cdot S\\\\F = d\cdot g\cdot h\cdot S\\\\F = 1030\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot100 \ m\cdot5 \ m^{2}}\\\\\boxed{F = 5 \ 150 \ 000 \ N = 5 \ 150 \ kN = 5,15 \ MN}\\\\1 \ kN = 1000 \ N\\1 \ MN = 1 \ 000 \ 000 \ N[/tex]
