Odpowiedź:
[tex]a)\ \ 3(x-4)=3x-12\\\\b)\ \ 5(2+4x)=10+20x\\\\c)\ \ 2(5a+7b-3)=10a+14b-6\\\\d)\ \ -(3r-5t)=-3r+5t\\\\e)\ \ -\frac{3}{4}(8x+12y)=-6x-9y\\\\f)\ \ -(-7a+9b)=7a-9b\\\\g)\ \ 2,5(-4p-10q)=-10p-25q\\\\h)\ \ -\frac{1}{2}(6a+8)=-3a-4 [/tex]
