zadanie 6 strona 199 matematyka z kluczem klasa5

[tex]1\frac{4}{5}:1\frac{1}{2}+\frac{1}{15}=\frac{9}{5}\cdot\frac{2}{3} +\frac{1}{15}=\frac{18}{15}+ \frac{1}{15} =\frac{19}{15} =1\frac{4}{15} [/tex]

2]

[tex](8\frac{1}{6}-4\frac{29}{30})\cdot\frac{3}{8}=(8\frac{5}{30}-4\frac{29}{30})\cdot\frac{3}{8}=(7\frac{35}{30}-4\frac{29}{30})\cdot\frac{3}{8}=3\frac{6}{30} \cdot\frac{3}{8}=\\ \\ 3\frac{1}{5}\cdot\frac{3}{8}=\frac{16}{5}\cdot\frac{3}{8}=\frac{6}{5}=1\frac{1}{5}[/tex]

3]

[tex]1\frac{2}{5}:2\frac{1}{3}+2\frac{1}{5}\cdot\frac{4}{11}=\frac{7}{5}\cdot\frac{3}{7}+\frac{11}{5}\cdot\frac{4}{11}=\frac{3}{5}+\frac{4}{5}=\frac{7}{5}=1 \frac{2}{5}[/tex]

4]

[tex]1\frac{1}{2}+\frac{1}{6}+\frac{4}{9}\cdot2\frac{2}{5}=1\frac{3}{6}+\frac{1}{6}+\frac{4}{9}\cdot\frac{12}{5}=1\frac{4}{6}+\frac{16}{15}=1\frac{20}{30}+ \frac{32}{30}=1 \frac{52}{30}=2\frac{22}{30}=2\frac{11}{15} [/tex]

Magda Magda · Answer 2 · 2022-01-24T19:25:00+01:00

Odpowiedź:

[tex]1\frac{4}{5}:1\frac{1}{2}+\frac{1}{15}=\frac{9}{5}:\frac{3}{2}+\frac{1}{15}=\frac{\not9^3}{5}\cdot\frac{2}{\not3_{1}}+\frac{1}{15}=\frac{6}{5}+\frac{1}{15}=\frac{18}{15}+\frac{1}{15}=\frac{19}{15}=1\frac{4}{15}\\\\\\(8\frac{1}{6}-4\frac{29}{30})\cdot\frac{3}{8}=(8\frac{5}{30}-4\frac{29}{30})\cdot\frac{3}{8}=(7\frac{35}{30}-4\frac{29}{30})\cdot\frac{3}{8}=3\frac{6}{30}\cdot\frac{3}{8}=3\frac{1}{5}\cdot\frac{3}{8}=\frac{\not16^2}{5}\cdot\frac{3}{\not8_{1}}= [/tex][tex]=\frac{6}{5}=1\frac{1}{5}\\\\\\1\frac{2}{5}:2\frac{1}{3}+2\frac{1}{5}\cdot\frac{4}{11}=\frac{7}{5}:\frac{7}{3}+\frac{\not11}{5}\cdot\frac{4}{\not11}=\frac{\not7}{5}\cdot\frac{3}{\not7}+\frac{4}{5}=\frac{3}{5}+\frac{4}{5}=\frac{7}{5}=1\frac{2}{5} [/tex]

[tex]1\frac{1}{2}+\frac{1}{6}+\frac{4}{9}\cdot2\frac{2}{5}=1\frac{3}{6}+\frac{1}{6}+\frac{4}{\not9_{3}}\cdot\frac{\not12^4}{5}=1\frac{4}{6}+\frac{16}{15}=1\frac{2}{3}+1\frac{1}{15}=1\frac{10}{15}+1\frac{1}{15}=2\frac{11}{15} [/tex]