Odpowiedź :
Odpowiedź:
zad1
V=2,4m³
d=1000kg/m³
V1=V/2
V1=2,4m³/2=1,2m³
Fw=dgV1
Fw=1000kg/m³*10N/kg*1,2m³
Fw=12000N
zad2
Fw=600N
d=1030kg/m³
V=Fw/d*g
V=600N/1030kg/m³*10N/kg
V=0,058m³
zad3
F1=2,5N
F2=1,9N
Fw=F1-F2
Fw=2,5-1,9N
Fw=0,6N
[tex]1.\\ Dane:\\V = 2,4 \ m^{3}\\V_{z} = 0,5V = 0,5\cdot2,4 \ m^{3} = 1,2 \ m^{3}\\d = 1000\frac{kg}{m^{3}}\\g = 10\frac{m}{s^{2}} = 10\frac{N}{kg}\\Szukane:\\F_{w} = ?\\\\Rozwiazanie\\\\F_{w} = d_{cieczy}\cdot g\cdot V_{zanurzonego \ ciala \ lub \ jego \ zanurzonej \ czesci}\\\\\underline{F_{w} = d\cdot g\cdot V_{z}}\\\\F_{w} = 1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot1,2 \ m^{3}}\\\\\boxed{F_{w} = 12 \ 000 \ N = 12 \ kN}\\\\(1 \ kN = 1000 \ N) [/tex]
[tex]2.\\Dane:\\F_{w} = 600 \ N\\d = 1030\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\Szukane:\\V_{z} = ?\\\\Rozwiazanie\\\\F_{w} = d\cdot g\cdot V_{z} \ \ /:(d\cdot g)\\\\V_{z} = \frac{F_{w}}{d\cdot g}\\\\V_{z} =\frac{600 \ N}{1030\frac{kg}{m^{3}}\cdot 10\frac{N}{kg}}\\\\\boxed{V_{z}\approx0,058 \ m^{3}}[/tex]
[tex]3.\\Dane:\\F = 2,5 \ N\\F_{z} = 1,9 \ N\\Szukane:\\F_{w}= ?\\\\F_{w} = F-F_{z}\\\\F_{w} = 2,5 \ N - 1,9 \ N\\\\\boxed{F_{w} = 0,6 \ N}[/tex]