Odpowiedź :
[tex]Dane:\\s = 1 \ km\\t = 13 \ min = \frac{13}{60} \ h\\Szukane:\\v = ?\\\\v = \frac{s}{t}\\\\v = \frac{1 \ km}{\frac{13}{60} \ h}\\\\\boxed{v\approx4,62\frac{km}{h}}[/tex]
[tex]Dane:\\s = 1 \ km\\t = 13 \ min = \frac{13}{60} \ h\\Szukane:\\v = ?\\\\v = \frac{s}{t}\\\\v = \frac{1 \ km}{\frac{13}{60} \ h}\\\\\boxed{v\approx4,62\frac{km}{h}}[/tex]