Podstawmy z x podaną wartość:
[tex][-\frac{1}{-\frac{1}{2}}+(-\frac{1}{2})^3]^2 \cdot\frac{8}{25} =[2+(-\frac{1}{8} )]^2\cdot\frac{8}{25} =[2-\frac{1}{8} ]^2\cdot\frac{8}{25} =\\\\(1\frac{7}{8} )^2\cdot\frac{8}{25}=(\frac{15}{8})^2\cdot \frac{8}{25}= \frac{225}{64}\cdot\frac{8}{25}= \frac{9}{8}=1\frac{1}{8}[/tex]
