Odpowiedź:
[tex]\frac{3}{\sqrt{2}+2 } +\frac{4}{2\sqrt{2}-1 } -\frac{5}{\sqrt{2} }\\ \frac{3(\sqrt{2} -2)}{-2} +\frac{4(2\sqrt{2}+1) }{7} -\frac{5\sqrt{2} }{2} \\\frac{3\sqrt{2}-6 }{-2} +\frac{8\sqrt{2}+4 }{7}-\frac{5\sqrt{2} }{2}\\ -\frac{3\sqrt{2}-6 }{2} +\frac{8\sqrt{2}+4 }{7}-\frac{5\sqrt{2} }{2}\\ \frac{-7(3\sqrt{2}-6)+2(8\sqrt{2}+4)-35\sqrt{2} }{14}\\ \frac{-21\sqrt{2}+42+16\sqrt{2}+8-35\sqrt{2} }{14}\\ \frac{-40\sqrt{2}+50 }{14}\\ \frac{2(-20\sqrt{2}+25) }{14}\\ \frac{-20\sqrt{2}+25 }{7}\\[/tex]
Szczegółowe wyjaśnienie:
