Odpowiedź:
Zadanie 1
[tex]a) 6(x-4)-12 = 6x-24-12= 6x-36\\b) -3(y+2)+4(x+2) = -3y-6+4x+8= -3y+4x+2\\c) 2(3a+x-7)-8(x-4+5a) = 6a+2x-14-8x+32-40a = -34a-6x+18\\d) 5a(a-3)-3a(a+5)= 5a^2-15a - 3a^2-15a = 2a^2\\e) 4-(x+5)+4(x-7) = 4-x-5+4x-28 = 3x-29\\f) x(x+7)+4x-9x^2+16=x^2+7x+4x-9x^2+16= -8x^2+11x+16[/tex]
Zadanie 2
[tex]a) (x+8)(3x-3)=3x^{2} -3x+24x-24=3x^{2} +21x-24\\b) (4a-3)(2+6a)=8a+24a^{2} -6-18a=24a^{2}-10a-6\\c) (3-x)(4x+8)=12x+23-4x^{2} -8x=-4x^{2} +4x+23\\d)(y+7)(8-2y)=8y-2y^{2} +56-14y=-2y^{2} -6y+56[/tex]
Zadanie 3
[tex]a) \frac{3x-6}{3}+4=\frac{3(x-2)}{3}+4=x-2+4=x+2\\\\b)\frac{15+5a}{5} -\frac{8a-4}{2}=\frac{5(3+a)}{5}-\frac{2(4a-2)}{2}=3+a-(4a-2)=3+a-4a+2=5-3a\\\\c) \frac{6x-2}{2}+\frac{10+20x}{5}= \frac{2(3x-1)}{2}+\frac{5(2+4x)}{5}= 3x-1+2+4x=7x+1\\\\d) 8*\frac{x-5}{4}-9*\frac{x-1}{3}=2(x-5)-3(x-1)=2x-10-3x+3=-x-7[/tex]
