Odpowiedź :
a) 2(2y+4)+2(5x+2)+2(y-1) = 4y+8 + 10x+4 + 2y-2 = 10x+6y+10
b) y+6+2(3x+4)+3y-7+2x = y+6+6x+8+3y-7+2x= 8x+4y+7
c) 7-y+2(x+7)+x-1+2y = 7-y+2x+14+x-1+2y = 3x+y+20
a) 2(2y+4)+2(5x+2)+2(y-1) = 4y+8 + 10x+4 + 2y-2 = 10x+6y+10
b) y+6+2(3x+4)+3y-7+2x = y+6+6x+8+3y-7+2x= 8x+4y+7
c) 7-y+2(x+7)+x-1+2y = 7-y+2x+14+x-1+2y = 3x+y+20