HCl + NaOH = NaCl + H2O
Chcl = 0,1 mol/dm3
Vhcl = ?
Vnaoh = 25 cm3 = 0,025 dm3
Cpnaoh = 18%
dnaoh = 1,2g/cm3 = 1200 g/dm3
Cm = (Cp * dr)/(Ms * 100%)
Cnaoh = (18% * 1200g/dm3)/(40g/mol * 100%)
Cnaoh = 0,18 * 30mol/dm3
Cnaoh = 5,4 mol/dm3
nnaoh = 5,4 mol/dm3 * 0,025 dm3 = 0,135 mol
1 mol NaOH - 1 mol HCl
0,135 mol NaOH - x mol HCl
x = 0,135
nhcl = 0,135 mol
Vhcl = 0,135mol/0,1mol/dm3 = 1,35 dm3 = 1350 cm3
odp: potrzeba 1350 cm3 0,1-molowego HCl
