zadanie 6
[tex]a) 3\frac{1}{3}:1*\frac{3}{10}=3\frac{1}{3}*\frac{3}{10}=\frac{10}{3}*\frac{3}{10}=1\\ \\ b)4\frac{7}{9}:5\frac{3}{7}*0=0\\ \\ c)1:\frac{5}{8}*\frac{5}{8}=\frac{8}{5}*\frac{5}{8}=1\\ \\[/tex]
zadanie 7
[tex]a) =1\frac{3}{5}*\frac{1}{4}=\frac{8}{5}*\frac{1}{4}=\frac{8}{20}=\frac{2}{5}\\ \\ b)=(\frac{56}{72}-\frac{47}{72}):\frac{5}{4}=\frac{9}{72}*\frac{4}{5}=\frac{1}{8}*\frac{4}{5}=\frac{4}{40}=\frac{1}{10}\\ \\ c) = 6*(\frac{4}{3})^{2}=6*\frac{16}{9}=\frac{96}{9}=10\frac{2}{3}\\[/tex]
[tex]d) = \frac{25}{49}*\frac{7}{5}=\frac{5}{7}\\ \\ e)=(\frac{4}{12}- \frac{3}{12} )^{2}=(\frac{1}{12} )^{2}=\frac{1}{144}\\\\f) = \frac{4}{25}+\frac{9}{2}*\frac{8}{3}=\frac{4}{25}+12=12\frac{4}{25}\\ \\ g)=5*\frac{1}{4}+15*\frac{1}{9}=\frac{5}{4}+\frac{15}{9}=\frac{45}{36}+\frac{60}{36}=\frac{105}{36}=2\frac{33}{36}=2\frac{11}{12}\\ \\ h)=\frac{1}{9}-(\frac{5}{6})^{2}=\frac{1}{9}-\frac{1}{36}=\frac{8}{72}-\frac{2}{72}=\frac{6}{72}[/tex]
Hasło: DROMADER
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