[tex]Dane:\\S_1 = 0,25 \ m^{2}\\F_1 = 50 \ N\\S_2 = 1,5 \ m^{2}\\Szukane:\\F_2 = ?\\\\Rozwiazanie\\\\\frac{F_1}{S_1} = \frac{F_2}{S_2}\\\\S_1\cdot F_2 = S_2\cdot F_1 \ \ /:S_1\\\\F_2 = \frac{S_2}{S_1}\cdot F_1\\\\F_2 = \frac{1,5 \ m^{2}}{0,25 \ m^{2}}\cdot 50 \ N\\\\F_2 = 6\cdot 50 \ N\\\\\boxed{F_2 = 300 \ N}[/tex]
Odp. Na duży tłok działa siła F₂ = 300 N.
