[tex]Dane:\\m = 26 \ kg\\S = 0,016 \ m^{2}\\g = 10\frac{N}{kg}\\Szukane:\\p = ?\\\\\\p = \frac{F}{S}\\\\F = m\cdot g\\\\p = \frac{m\cdot g}{S}\\\\p = \frac{26 \ kg\cdot10\frac{N}{kg}}{0,016 \ m^{2}}\\\\p = \frac{260 \ N}{0,016 \ m^{2}}\\\\p = 16 \ 250\frac{N}{m^{2}}\\\\\boxed{p = 16 \ 250 \ Pa = 16,25 \ kPa}\\\\(1 \ kPa = 1000 \ Pa)[/tex]
