Szczegółowe wyjaśnienie:
[tex]a)\ x-3<16\qquad|+3\\\\\huge\boxed{x<19\to x\in(-\infty,\ 19)}[/tex]
[tex]b)\ 2x+1\geq x-3\qquad|-x\\\\x+1\geq-3\qquad|-1\\\\\huge\boxed{x\geq-4\to x\in\left<-4,\ \infty\right)}[/tex]
[tex]c)\ x-4\leq6x+16\qquad|+4\\\\x\leq6x+20\qquad|-6x\\\\-5x\leq20\qquad|:(-5)\\\\\huge\boxed{x\geq-4\to x\in\left<-4,\ \infty\right)}[/tex]
