Rozwiązane

√2+√8-√32=
3√3+√48+ √75=
2√8-√18+5√50=



Odpowiedź :

Potato666

[tex] \sqrt{2} + \sqrt{8} - \sqrt{32} = \sqrt{2} + 2 \sqrt{2} - 4 \sqrt{2} = - \sqrt{2} [/tex]

[tex]3 \sqrt{3} + \sqrt{48} + \sqrt{75} = 3 \sqrt{3} + 4 \sqrt{3} + 5 \sqrt{3} = 12 \sqrt{3} [/tex]

[tex]2 \sqrt{8} - \sqrt{18} + 5 \sqrt{50} = 4 \sqrt{2} - 3 \sqrt{2} + 25 \sqrt{2} = 26 \sqrt{2} [/tex]

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Magda

Odpowiedź:

[tex]\sqrt{2}+\sqrt{8}-\sqrt{32}=\sqrt{2}+\sqrt{4\cdot2}-\sqrt{16\cdot2}=\sqrt{2}+2\sqrt{2}-4\sqrt{2}=3\sqrt{2}-4\sqrt{2}=-\sqrt{2}\\\\\\3\sqrt{3}+\sqrt{48}+\sqrt{75}=3\sqrt{3}+\sqrt{16\cdot3}+\sqrt{25\cdot3}=3\sqrt{3}+4\sqrt{3}+5\sqrt{3}=12\sqrt{3}\\\\\\2\sqrt{8}-\sqrt{18}+5\sqrt{50}=2\sqrt{4\cdot2}-\sqrt{9\cdot2}+5\sqrt{25\cdot2}=2\cdot2\sqrt{2}-3\sqrt{2}+5\cdot5\sqrt{2}=\\\\=4\sqrt{2}-3\sqrt{2}+25\sqrt{2}=\sqrt{2}+25\sqrt{2}=26\sqrt{2}[/tex]

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