Odpowiedź :
[tex](3\frac{2}{9}+4\frac{5}{6})\cdot9=(7\frac{4}{18}+\frac{15}{18})\cdot\frac{7}{1}=7\frac{19}{18}\cdot\frac{7}{1}=\\ \\ 8\frac{1}{18}\cdot\frac{7}{1}=8\cdot\frac{7}{1} +\frac{1}{18}\cdot \frac{7}{1} = 56+\frac{7}{18}=56\frac{7}{18}[/tex]