Odpowiedź :
x² + 3x - 4 = 0
Δ = 9 - 4*-4*1=9+16=25
√Δ = 5
x₁ = (-3+5)/2 = 2/2 = 1
x₂ = (-3-5)/2 = -8/2 = -4
[tex]x^2+3x-4=0\\x^2-x+4x-4=0\\x(x-1)+4(x-1)=0\\(x+4)(x-1)=0\\x=-4 \vee x=1[/tex]
x² + 3x - 4 = 0
Δ = 9 - 4*-4*1=9+16=25
√Δ = 5
x₁ = (-3+5)/2 = 2/2 = 1
x₂ = (-3-5)/2 = -8/2 = -4
[tex]x^2+3x-4=0\\x^2-x+4x-4=0\\x(x-1)+4(x-1)=0\\(x+4)(x-1)=0\\x=-4 \vee x=1[/tex]